Solve 5/3x-6y+12=0

$$\frac { 5 } { 3 } x - 6 y + 12 = 0$$

Solve for x

$$x=\frac{18\left(y-2\right)}{5}$$

Steps for Solving Linear Equation

Add 6y to both sides. Anything plus zero gives itself.

$$\frac{5}{3}x+12=6y$$

Subtract 12 from both sides.

$$\frac{5}{3}x=6y-12$$

Divide both sides of the equation by \frac{5}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{3}x}{\frac{5}{3}}=\frac{6y-12}{\frac{5}{3}}$$

Dividing by \frac{5}{3} undoes the multiplication by \frac{5}{3}.

$$x=\frac{6y-12}{\frac{5}{3}}$$

Divide -12+6y by \frac{5}{3} by multiplying -12+6y by the reciprocal of \frac{5}{3}.

$$x=\frac{18y-36}{5}$$

Solve for y

$$y=\frac{5x}{18}+2$$

Steps for Solving Linear Equation

Subtract \frac{5}{3}x from both sides. Anything subtracted from zero gives its negation.

$$-6y+12=-\frac{5}{3}x$$

Subtract 12 from both sides.

$$-6y=-\frac{5}{3}x-12$$

The equation is in standard form.

$$-6y=-\frac{5x}{3}-12$$

Divide both sides by -6.

$$\frac{-6y}{-6}=\frac{-\frac{5x}{3}-12}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$y=\frac{-\frac{5x}{3}-12}{-6}$$

Divide -\frac{5x}{3}-12 by -6.

$$y=\frac{5x}{18}+2$$