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\frac{5}{3}x-3+\frac{1}{4}x=-\frac{5}{4}
Add \frac{1}{4}x to both sides.
\frac{23}{12}x-3=-\frac{5}{4}
Combine \frac{5}{3}x and \frac{1}{4}x to get \frac{23}{12}x.
\frac{23}{12}x=-\frac{5}{4}+3
Add 3 to both sides.
\frac{23}{12}x=-\frac{5}{4}+\frac{12}{4}
Convert 3 to fraction \frac{12}{4}.
\frac{23}{12}x=\frac{-5+12}{4}
Since -\frac{5}{4} and \frac{12}{4} have the same denominator, add them by adding their numerators.
\frac{23}{12}x=\frac{7}{4}
Add -5 and 12 to get 7.
x=\frac{7}{4}\times \frac{12}{23}
Multiply both sides by \frac{12}{23}, the reciprocal of \frac{23}{12}.
x=\frac{7\times 12}{4\times 23}
Multiply \frac{7}{4} times \frac{12}{23} by multiplying numerator times numerator and denominator times denominator.
x=\frac{84}{92}
Do the multiplications in the fraction \frac{7\times 12}{4\times 23}.
x=\frac{21}{23}
Reduce the fraction \frac{84}{92} to lowest terms by extracting and canceling out 4.