Solve 5/3x+7/6y=27

$$\frac { 5 } { 3 } x + \frac { 7 } { 6 } y = 27$$

Solve for x

$$x=-\frac{7y}{10}+\frac{81}{5}$$

Steps for Solving Linear Equation

Subtract \frac{7}{6}y from both sides.

$$\frac{5}{3}x=27-\frac{7}{6}y$$

The equation is in standard form.

$$\frac{5}{3}x=-\frac{7y}{6}+27$$

Divide both sides of the equation by \frac{5}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{3}x}{\frac{5}{3}}=\frac{-\frac{7y}{6}+27}{\frac{5}{3}}$$

Dividing by \frac{5}{3} undoes the multiplication by \frac{5}{3}.

$$x=\frac{-\frac{7y}{6}+27}{\frac{5}{3}}$$

Divide 27-\frac{7y}{6} by \frac{5}{3} by multiplying 27-\frac{7y}{6} by the reciprocal of \frac{5}{3}.

$$x=-\frac{7y}{10}+\frac{81}{5}$$

Solve for y

$$y=\frac{162-10x}{7}$$

Steps for Solving Linear Equation

Subtract \frac{5}{3}x from both sides.

$$\frac{7}{6}y=27-\frac{5}{3}x$$

The equation is in standard form.

$$\frac{7}{6}y=-\frac{5x}{3}+27$$

Divide both sides of the equation by \frac{7}{6}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{7}{6}y}{\frac{7}{6}}=\frac{-\frac{5x}{3}+27}{\frac{7}{6}}$$

Dividing by \frac{7}{6} undoes the multiplication by \frac{7}{6}.

$$y=\frac{-\frac{5x}{3}+27}{\frac{7}{6}}$$

Divide 27-\frac{5x}{3} by \frac{7}{6} by multiplying 27-\frac{5x}{3} by the reciprocal of \frac{7}{6}.

$$y=\frac{162-10x}{7}$$