Solve 5/3-2+1+c=3

$$\frac { 5 } { 3 } - 2 + 1 + c = 3$$

Solve for c

$$c = \frac{7}{3} = 2\frac{1}{3} \approx 2.333333333$$

Steps for Solving Linear Equation

Convert 2 to fraction \frac{6}{3}.

$$\frac{5}{3}-\frac{6}{3}+1+c=3$$

Since \frac{5}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-6}{3}+1+c=3$$

Subtract 6 from 5 to get -1.

$$-\frac{1}{3}+1+c=3$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{1}{3}+\frac{3}{3}+c=3$$

Since -\frac{1}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{-1+3}{3}+c=3$$

Add -1 and 3 to get 2.

$$\frac{2}{3}+c=3$$

Subtract \frac{2}{3} from both sides.

$$c=3-\frac{2}{3}$$

Convert 3 to fraction \frac{9}{3}.

$$c=\frac{9}{3}-\frac{2}{3}$$

Since \frac{9}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$c=\frac{9-2}{3}$$

Subtract 2 from 9 to get 7.

$$c=\frac{7}{3}$$