Solve 5/3*frac{270sqrt{39}+120sqrt{3}}{9333}

$$\frac { 5 } { 3 } \times \frac { 270 \sqrt { 39 } + 120 \sqrt { 3 } } { 9333 }$$

Evaluate

$$\frac{50\sqrt{39}}{1037}+\frac{200\sqrt{3}}{9333}\approx 0.338225572$$

Solution Steps

Multiply \frac{5}{3} times \frac{270\sqrt{39}+120\sqrt{3}}{9333} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\left(270\sqrt{39}+120\sqrt{3}\right)}{3\times 9333}$$

Multiply 3 and 9333 to get 27999.

$$\frac{5\left(270\sqrt{39}+120\sqrt{3}\right)}{27999}$$

Use the distributive property to multiply 5 by 270\sqrt{39}+120\sqrt{3}.

$$\frac{1350\sqrt{39}+600\sqrt{3}}{27999}$$

Factor

$$\frac{50 {(4 \sqrt{3} + 9 \sqrt{39})}}{9333} = 0.33822557171253126$$