Solve 5/21*2/7+219/21*5/7

$$\frac { 5 } { 21 } \times \frac { 2 } { 7 } + 2 \frac { 19 } { 21 } \times \frac { 5 } { 7 }$$

Evaluate

$$\frac{15}{7}\approx 2.142857143$$

Solution Steps

Multiply \frac{5}{21} times \frac{2}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 2}{21\times 7}+\frac{2\times 21+19}{21}\times \frac{5}{7}$$

Do the multiplications in the fraction \frac{5\times 2}{21\times 7}.

$$\frac{10}{147}+\frac{2\times 21+19}{21}\times \frac{5}{7}$$

Multiply 2 and 21 to get 42.

$$\frac{10}{147}+\frac{42+19}{21}\times \frac{5}{7}$$

Add 42 and 19 to get 61.

$$\frac{10}{147}+\frac{61}{21}\times \frac{5}{7}$$

Multiply \frac{61}{21} times \frac{5}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{10}{147}+\frac{61\times 5}{21\times 7}$$

Do the multiplications in the fraction \frac{61\times 5}{21\times 7}.

$$\frac{10}{147}+\frac{305}{147}$$

Since \frac{10}{147} and \frac{305}{147} have the same denominator, add them by adding their numerators.

$$\frac{10+305}{147}$$

Add 10 and 305 to get 315.

$$\frac{315}{147}$$

Reduce the fraction \frac{315}{147} to lowest terms by extracting and canceling out 21.

$$\frac{15}{7}$$

Factor

$$\frac{3 \cdot 5}{7} = 2\frac{1}{7} = 2.142857142857143$$