Solve for x
x = \frac{25}{3} = 8\frac{1}{3} \approx 8.333333333
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\left(x-4\right)\times 5-\left(2x+5\right)=0
Variable x cannot be equal to any of the values -\frac{5}{2},4 since division by zero is not defined. Multiply both sides of the equation by \left(x-4\right)\left(2x+5\right), the least common multiple of 2x+5,x-4.
5x-20-\left(2x+5\right)=0
Use the distributive property to multiply x-4 by 5.
5x-20-2x-5=0
To find the opposite of 2x+5, find the opposite of each term.
3x-20-5=0
Combine 5x and -2x to get 3x.
3x-25=0
Subtract 5 from -20 to get -25.
3x=25
Add 25 to both sides. Anything plus zero gives itself.
x=\frac{25}{3}
Divide both sides by 3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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