Solve for x
x=-3
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\frac{5}{2}x+\frac{5}{2}\left(-1\right)+3=2x-1
Use the distributive property to multiply \frac{5}{2} by x-1.
\frac{5}{2}x-\frac{5}{2}+3=2x-1
Multiply \frac{5}{2} and -1 to get -\frac{5}{2}.
\frac{5}{2}x-\frac{5}{2}+\frac{6}{2}=2x-1
Convert 3 to fraction \frac{6}{2}.
\frac{5}{2}x+\frac{-5+6}{2}=2x-1
Since -\frac{5}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.
\frac{5}{2}x+\frac{1}{2}=2x-1
Add -5 and 6 to get 1.
\frac{5}{2}x+\frac{1}{2}-2x=-1
Subtract 2x from both sides.
\frac{1}{2}x+\frac{1}{2}=-1
Combine \frac{5}{2}x and -2x to get \frac{1}{2}x.
\frac{1}{2}x=-1-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
\frac{1}{2}x=-\frac{2}{2}-\frac{1}{2}
Convert -1 to fraction -\frac{2}{2}.
\frac{1}{2}x=\frac{-2-1}{2}
Since -\frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{2}x=-\frac{3}{2}
Subtract 1 from -2 to get -3.
x=-\frac{3}{2}\times 2
Multiply both sides by 2, the reciprocal of \frac{1}{2}.
x=-3
Cancel out 2 and 2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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