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\frac{5\left(\sqrt{6}-\sqrt{7}\right)}{\left(\sqrt{6}+\sqrt{7}\right)\left(\sqrt{6}-\sqrt{7}\right)}
Rationalize the denominator of \frac{5}{\sqrt{6}+\sqrt{7}} by multiplying numerator and denominator by \sqrt{6}-\sqrt{7}.
\frac{5\left(\sqrt{6}-\sqrt{7}\right)}{\left(\sqrt{6}\right)^{2}-\left(\sqrt{7}\right)^{2}}
Consider \left(\sqrt{6}+\sqrt{7}\right)\left(\sqrt{6}-\sqrt{7}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{5\left(\sqrt{6}-\sqrt{7}\right)}{6-7}
Square \sqrt{6}. Square \sqrt{7}.
\frac{5\left(\sqrt{6}-\sqrt{7}\right)}{-1}
Subtract 7 from 6 to get -1.
-5\left(\sqrt{6}-\sqrt{7}\right)
Anything divided by -1 gives its opposite.
-5\sqrt{6}+5\sqrt{7}
Use the distributive property to multiply -5 by \sqrt{6}-\sqrt{7}.