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\frac{5\sqrt{2}}{\left(\sqrt{2}\right)^{2}}-\frac{2}{\sqrt{8}}
Rationalize the denominator of \frac{5}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{5\sqrt{2}}{2}-\frac{2}{\sqrt{8}}
The square of \sqrt{2} is 2.
\frac{5\sqrt{2}}{2}-\frac{2}{2\sqrt{2}}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{5\sqrt{2}}{2}-\frac{2\sqrt{2}}{2\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{2}{2\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{5\sqrt{2}}{2}-\frac{2\sqrt{2}}{2\times 2}
The square of \sqrt{2} is 2.
\frac{5\sqrt{2}}{2}-\frac{\sqrt{2}}{2}
Cancel out 2 in both numerator and denominator.
2\sqrt{2}
Combine \frac{5\sqrt{2}}{2} and -\frac{\sqrt{2}}{2} to get 2\sqrt{2}.