Solve 5*3/4*3+23*3/4*3+5*2/6*2

$$\frac { 5 \times 3 } { 4 \times 3 } + \frac { 23 \times 3 } { 4 \times 3 } + \frac { 5 \times 2 } { 6 \times 2 }$$

Evaluate

$$\frac{47}{6}\approx 7.833333333$$

Solution Steps

Cancel out 3 in both numerator and denominator.

$$\frac{5}{4}+\frac{23\times 3}{4\times 3}+\frac{5\times 2}{6\times 2}$$

Cancel out 3 in both numerator and denominator.

$$\frac{5}{4}+\frac{23}{4}+\frac{5\times 2}{6\times 2}$$

Since \frac{5}{4} and \frac{23}{4} have the same denominator, add them by adding their numerators.

$$\frac{5+23}{4}+\frac{5\times 2}{6\times 2}$$

Add 5 and 23 to get 28.

$$\frac{28}{4}+\frac{5\times 2}{6\times 2}$$

Divide 28 by 4 to get 7.

$$7+\frac{5\times 2}{6\times 2}$$

Cancel out 2 in both numerator and denominator.

$$7+\frac{5}{2\times 3}$$

Multiply 2 and 3 to get 6.

$$7+\frac{5}{6}$$

Convert 7 to fraction \frac{42}{6}.

$$\frac{42}{6}+\frac{5}{6}$$

Since \frac{42}{6} and \frac{5}{6} have the same denominator, add them by adding their numerators.

$$\frac{42+5}{6}$$

Add 42 and 5 to get 47.

$$\frac{47}{6}$$

Factor

$$\frac{47}{2 \cdot 3} = 7\frac{5}{6} = 7.833333333333333$$