Solve frac{5^{2}-2^3*3}{(2^3+3*2^2)div(2^5*5)}=

$$\frac { 5 ^ { 2 } - 2 ^ { 3 } \cdot 3 } { ( 2 ^ { 3 } + 3 \cdot 2 ^ { 2 } ) \div ( 2 ^ { 5 } \cdot 5 ) } =$$

Evaluate

$$8$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\frac{25-2^{3}\times 3}{\frac{2^{3}+3\times 2^{2}}{2^{5}\times 5}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{25-8\times 3}{\frac{2^{3}+3\times 2^{2}}{2^{5}\times 5}}$$

Multiply 8 and 3 to get 24.

$$\frac{25-24}{\frac{2^{3}+3\times 2^{2}}{2^{5}\times 5}}$$

Subtract 24 from 25 to get 1.

$$\frac{1}{\frac{2^{3}+3\times 2^{2}}{2^{5}\times 5}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{1}{\frac{8+3\times 2^{2}}{2^{5}\times 5}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{1}{\frac{8+3\times 4}{2^{5}\times 5}}$$

Multiply 3 and 4 to get 12.

$$\frac{1}{\frac{8+12}{2^{5}\times 5}}$$

Add 8 and 12 to get 20.

$$\frac{1}{\frac{20}{2^{5}\times 5}}$$

Calculate 2 to the power of 5 and get 32.

$$\frac{1}{\frac{20}{32\times 5}}$$

Multiply 32 and 5 to get 160.

$$\frac{1}{\frac{20}{160}}$$

Reduce the fraction \frac{20}{160} to lowest terms by extracting and canceling out 20.

$$\frac{1}{\frac{1}{8}}$$

Divide 1 by \frac{1}{8} by multiplying 1 by the reciprocal of \frac{1}{8}.

$$1\times 8$$

Multiply 1 and 8 to get 8.

$$8$$

Factor

$$2^{3}$$