Solve 5+3^2-24div6*2/[5+3(2^3-5)]+sqrt{9}

$$\frac { 5 + 3 ^ { 2 } - 24 \div 6 \times 2 } { [ 5 + 3 ( 2 ^ { 3 } - 5 ) ] + \sqrt { 9 } }$$

Evaluate

$$\frac{6}{17}\approx 0.352941176$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\frac{5+9-\frac{24}{6}\times 2}{5+3\left(2^{3}-5\right)+\sqrt{9}}$$

Add 5 and 9 to get 14.

$$\frac{14-\frac{24}{6}\times 2}{5+3\left(2^{3}-5\right)+\sqrt{9}}$$

Divide 24 by 6 to get 4.

$$\frac{14-4\times 2}{5+3\left(2^{3}-5\right)+\sqrt{9}}$$

Multiply 4 and 2 to get 8.

$$\frac{14-8}{5+3\left(2^{3}-5\right)+\sqrt{9}}$$

Subtract 8 from 14 to get 6.

$$\frac{6}{5+3\left(2^{3}-5\right)+\sqrt{9}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{6}{5+3\left(8-5\right)+\sqrt{9}}$$

Subtract 5 from 8 to get 3.

$$\frac{6}{5+3\times 3+\sqrt{9}}$$

Multiply 3 and 3 to get 9.

$$\frac{6}{5+9+\sqrt{9}}$$

Add 5 and 9 to get 14.

$$\frac{6}{14+\sqrt{9}}$$

Calculate the square root of 9 and get 3.

$$\frac{6}{14+3}$$

Add 14 and 3 to get 17.

$$\frac{6}{17}$$

Factor

$$\frac{2 \cdot 3}{17} = 0.35294117647058826$$