Solve for x
x=1
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-3x=\frac{10}{13}-\frac{49}{13}
Subtract \frac{49}{13} from both sides.
-3x=\frac{10-49}{13}
Since \frac{10}{13} and \frac{49}{13} have the same denominator, subtract them by subtracting their numerators.
-3x=\frac{-39}{13}
Subtract 49 from 10 to get -39.
-3x=-3
Divide -39 by 13 to get -3.
x=\frac{-3}{-3}
Divide both sides by -3.
x=1
Divide -3 by -3 to get 1.
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