Solve 48^2-32^2/21^2-19^2

$$\frac { 48 ^ { 2 } - 32 ^ { 2 } } { 21 ^ { 2 } - 19 ^ { 2 } }$$

Evaluate

$$16$$

Solution Steps

Calculate 48 to the power of 2 and get 2304.

$$\frac{2304-32^{2}}{21^{2}-19^{2}}$$

Calculate 32 to the power of 2 and get 1024.

$$\frac{2304-1024}{21^{2}-19^{2}}$$

Subtract 1024 from 2304 to get 1280.

$$\frac{1280}{21^{2}-19^{2}}$$

Calculate 21 to the power of 2 and get 441.

$$\frac{1280}{441-19^{2}}$$

Calculate 19 to the power of 2 and get 361.

$$\frac{1280}{441-361}$$

Subtract 361 from 441 to get 80.

$$\frac{1280}{80}$$

Divide 1280 by 80 to get 16.

$$16$$

Factor

$$2^{4}$$