Solve 45/15=?/1quad27/9=?/1

$$\frac { 45 } { 15 } = \frac { ? } { 1 } \quad \frac { 27 } { 9 } = \frac { ? } { 1 }$$

Verify

Solution Steps

Divide 1 by 1 to get 1.

$$\frac{45}{15}=1\times \frac{27}{9}\text{ and }\frac{1}{1}\times \frac{27}{9}=\frac{1}{1}$$

Divide 1 by 1 to get 1.

$$\frac{45}{15}=1\times \frac{27}{9}\text{ and }1\times \frac{27}{9}=\frac{1}{1}$$

Divide 1 by 1 to get 1.

$$\frac{45}{15}=1\times \frac{27}{9}\text{ and }1\times \frac{27}{9}=1$$

Divide 45 by 15 to get 3.

$$3=1\times \frac{27}{9}\text{ and }1\times \frac{27}{9}=1$$

Divide 27 by 9 to get 3.

$$3=1\times 3\text{ and }1\times \frac{27}{9}=1$$

Multiply 1 and 3 to get 3.

$$3=3\text{ and }1\times \frac{27}{9}=1$$

Compare 3 and 3.

$$\text{true}\text{ and }1\times \frac{27}{9}=1$$

Divide 27 by 9 to get 3.

$$\text{true}\text{ and }1\times 3=1$$

Multiply 1 and 3 to get 3.

$$\text{true}\text{ and }3=1$$

Compare 3 and 1.

$$\text{true}\text{ and }\text{false}$$

The conjunction of \text{true} and \text{false} is \text{false}.

$$\text{false}$$