Solve 44(T^3)/24+[22(T^2)t]/21=924

$$\frac { 44 ( T ^ { 3 } ) } { 24 } + \frac { [ 22 ( T ^ { 2 } ) t ] } { 21 } = 924$$

Solve for t

$$t=-\frac{7T}{4}+\frac{882}{T^{2}}$$

$$T\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 168, the least common multiple of 24,21.

$$7\times 44T^{3}+8\times 22T^{2}t=155232$$

Multiply 7 and 44 to get 308.

$$308T^{3}+8\times 22T^{2}t=155232$$

Multiply 8 and 22 to get 176.

$$308T^{3}+176T^{2}t=155232$$

Subtract 308T^{3} from both sides.

$$176T^{2}t=155232-308T^{3}$$

Divide both sides by 176T^{2}.

$$\frac{176T^{2}t}{176T^{2}}=\frac{155232-308T^{3}}{176T^{2}}$$

Dividing by 176T^{2} undoes the multiplication by 176T^{2}.

$$t=\frac{155232-308T^{3}}{176T^{2}}$$

Divide 155232-308T^{3} by 176T^{2}.

$$t=-\frac{7T}{4}+\frac{882}{T^{2}}$$