Solve 40w^2x^2/48w^5x

$$\frac { 40 w ^ { 2 } x ^ { 2 } } { 48 w ^ { 5 } x }$$

Evaluate

$$\frac{5x}{6w^{3}}$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{40^{1}w^{2}x^{2}}{48^{1}w^{5}x^{1}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{40^{1}}{48^{1}}w^{2-5}x^{2-1}$$

Subtract 5 from 2.

$$\frac{40^{1}}{48^{1}}w^{-3}x^{2-1}$$

Subtract 1 from 2.

$$\frac{40^{1}}{48^{1}}\times \frac{1}{w^{3}}x^{1}$$

Reduce the fraction \frac{40}{48} to lowest terms by extracting and canceling out 8.

$$\frac{5}{6}\times \frac{1}{w^{3}}x$$

Differentiate w.r.t. x

$$\frac{5}{6w^{3}}$$