Solve 40/56x+(2.3y-1.0y-x)*40/74=2.03*40/1000

$$\frac { 40 } { 56 } x + ( 2.3 y - 1.0 y - x ) \times \frac { 40 } { 74 } = 2.03 \times \frac { 40 } { 1000 }$$

Solve for x

$$x=-\frac{182y}{45}+\frac{52577}{112500}$$

Steps for Solving Linear Equation

Reduce the fraction \frac{40}{56} to lowest terms by extracting and canceling out 8.

$$\frac{5}{7}x+\left(2.3y-y-x\right)\times \frac{40}{74}=2.03\times \frac{40}{1000}$$

Combine 2.3y and -y to get 1.3y.

$$\frac{5}{7}x+\left(1.3y-x\right)\times \frac{40}{74}=2.03\times \frac{40}{1000}$$

Reduce the fraction \frac{40}{74} to lowest terms by extracting and canceling out 2.

$$\frac{5}{7}x+\left(1.3y-x\right)\times \frac{20}{37}=2.03\times \frac{40}{1000}$$

Use the distributive property to multiply 1.3y-x by \frac{20}{37}.

$$\frac{5}{7}x+\frac{26}{37}y-\frac{20}{37}x=2.03\times \frac{40}{1000}$$

Combine \frac{5}{7}x and -\frac{20}{37}x to get \frac{45}{259}x.

$$\frac{45}{259}x+\frac{26}{37}y=2.03\times \frac{40}{1000}$$

Reduce the fraction \frac{40}{1000} to lowest terms by extracting and canceling out 40.

$$\frac{45}{259}x+\frac{26}{37}y=2.03\times \frac{1}{25}$$

Multiply 2.03 and \frac{1}{25} to get \frac{203}{2500}.

$$\frac{45}{259}x+\frac{26}{37}y=\frac{203}{2500}$$

Subtract \frac{26}{37}y from both sides.

$$\frac{45}{259}x=\frac{203}{2500}-\frac{26}{37}y$$

The equation is in standard form.

$$\frac{45}{259}x=-\frac{26y}{37}+\frac{203}{2500}$$

Divide both sides of the equation by \frac{45}{259}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{45}{259}x}{\frac{45}{259}}=\frac{-\frac{26y}{37}+\frac{203}{2500}}{\frac{45}{259}}$$

Dividing by \frac{45}{259} undoes the multiplication by \frac{45}{259}.

$$x=\frac{-\frac{26y}{37}+\frac{203}{2500}}{\frac{45}{259}}$$

Divide \frac{203}{2500}-\frac{26y}{37} by \frac{45}{259} by multiplying \frac{203}{2500}-\frac{26y}{37} by the reciprocal of \frac{45}{259}.

$$x=-\frac{182y}{45}+\frac{52577}{112500}$$

Solve for y

$$y=-\frac{45x}{182}+\frac{7511}{65000}$$

Steps for Solving Linear Equation

Reduce the fraction \frac{40}{56} to lowest terms by extracting and canceling out 8.

$$\frac{5}{7}x+\left(2.3y-y-x\right)\times \frac{40}{74}=2.03\times \frac{40}{1000}$$

Combine 2.3y and -y to get 1.3y.

$$\frac{5}{7}x+\left(1.3y-x\right)\times \frac{40}{74}=2.03\times \frac{40}{1000}$$

Reduce the fraction \frac{40}{74} to lowest terms by extracting and canceling out 2.

$$\frac{5}{7}x+\left(1.3y-x\right)\times \frac{20}{37}=2.03\times \frac{40}{1000}$$

Use the distributive property to multiply 1.3y-x by \frac{20}{37}.

$$\frac{5}{7}x+\frac{26}{37}y-\frac{20}{37}x=2.03\times \frac{40}{1000}$$

Combine \frac{5}{7}x and -\frac{20}{37}x to get \frac{45}{259}x.

$$\frac{45}{259}x+\frac{26}{37}y=2.03\times \frac{40}{1000}$$

Reduce the fraction \frac{40}{1000} to lowest terms by extracting and canceling out 40.

$$\frac{45}{259}x+\frac{26}{37}y=2.03\times \frac{1}{25}$$

Multiply 2.03 and \frac{1}{25} to get \frac{203}{2500}.

$$\frac{45}{259}x+\frac{26}{37}y=\frac{203}{2500}$$

Subtract \frac{45}{259}x from both sides.

$$\frac{26}{37}y=\frac{203}{2500}-\frac{45}{259}x$$

The equation is in standard form.

$$\frac{26}{37}y=-\frac{45x}{259}+\frac{203}{2500}$$

Divide both sides of the equation by \frac{26}{37}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{26}{37}y}{\frac{26}{37}}=\frac{-\frac{45x}{259}+\frac{203}{2500}}{\frac{26}{37}}$$

Dividing by \frac{26}{37} undoes the multiplication by \frac{26}{37}.

$$y=\frac{-\frac{45x}{259}+\frac{203}{2500}}{\frac{26}{37}}$$

Divide \frac{203}{2500}-\frac{45x}{259} by \frac{26}{37} by multiplying \frac{203}{2500}-\frac{45x}{259} by the reciprocal of \frac{26}{37}.

$$y=-\frac{45x}{182}+\frac{7511}{65000}$$