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Solve for x_7
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x_{7}\left(40+12+16\times 3\right)=10\times 36.5
Variable x_{7} cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 10x_{7}, the least common multiple of 10,x_{7}.
x_{7}\left(52+16\times 3\right)=10\times 36.5
Add 40 and 12 to get 52.
x_{7}\left(52+48\right)=10\times 36.5
Multiply 16 and 3 to get 48.
x_{7}\times 100=10\times 36.5
Add 52 and 48 to get 100.
x_{7}\times 100=365
Multiply 10 and 36.5 to get 365.
x_{7}=\frac{365}{100}
Divide both sides by 100.
x_{7}=\frac{73}{20}
Reduce the fraction \frac{365}{100} to lowest terms by extracting and canceling out 5.