Solve 4x/6+3/12*7/10-4/3=6

$$\frac { 4 x } { 6 } + \frac { 3 } { 12 } \times \frac { 7 } { 10 } - \frac { 4 } { 3 } = 6$$

Solve for x

$$x = \frac{859}{80} = 10\frac{59}{80} = 10.7375$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 60, the least common multiple of 6,12,10,3.

$$10\times 4x+15\times \frac{7}{10}-80=360$$

Multiply 10 and 4 to get 40.

$$40x+15\times \frac{7}{10}-80=360$$

Express 15\times \frac{7}{10} as a single fraction.

$$40x+\frac{15\times 7}{10}-80=360$$

Multiply 15 and 7 to get 105.

$$40x+\frac{105}{10}-80=360$$

Reduce the fraction \frac{105}{10} to lowest terms by extracting and canceling out 5.

$$40x+\frac{21}{2}-80=360$$

Convert 80 to fraction \frac{160}{2}.

$$40x+\frac{21}{2}-\frac{160}{2}=360$$

Since \frac{21}{2} and \frac{160}{2} have the same denominator, subtract them by subtracting their numerators.

$$40x+\frac{21-160}{2}=360$$

Subtract 160 from 21 to get -139.

$$40x-\frac{139}{2}=360$$

Add \frac{139}{2} to both sides.

$$40x=360+\frac{139}{2}$$

Convert 360 to fraction \frac{720}{2}.

$$40x=\frac{720}{2}+\frac{139}{2}$$

Since \frac{720}{2} and \frac{139}{2} have the same denominator, add them by adding their numerators.

$$40x=\frac{720+139}{2}$$

Add 720 and 139 to get 859.

$$40x=\frac{859}{2}$$

Divide both sides by 40.

$$x=\frac{\frac{859}{2}}{40}$$

Express \frac{\frac{859}{2}}{40} as a single fraction.

$$x=\frac{859}{2\times 40}$$

Multiply 2 and 40 to get 80.

$$x=\frac{859}{80}$$