Solve 4x^25y/2545=1

$$\frac { 4 x ^ { 2 } 5 y } { 2545 } = 1$$

Solve for y

$$y=\frac{509}{4x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides by 2545.

$$4x^{2}\times 5y=2545$$

Multiply 4 and 5 to get 20.

$$20x^{2}y=2545$$

Divide both sides by 20x^{2}.

$$\frac{20x^{2}y}{20x^{2}}=\frac{2545}{20x^{2}}$$

Dividing by 20x^{2} undoes the multiplication by 20x^{2}.

$$y=\frac{2545}{20x^{2}}$$

Divide 2545 by 20x^{2}.

$$y=\frac{509}{4x^{2}}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{509}y^{-\frac{1}{2}}}{2}$$

$$x=\frac{\sqrt{509}y^{-\frac{1}{2}}}{2}\text{, }y\neq 0$$

Solve for x

$$x=\frac{\sqrt{\frac{509}{y}}}{2}$$

$$x=-\frac{\sqrt{\frac{509}{y}}}{2}\text{, }y>0$$