Solve 4x^2-3/x-2-8x-3/x-2

$$\frac { 4 x ^ { 2 } - 3 } { x - 2 } - \frac { 8 x - 3 } { x - 2 }$$

Evaluate

$$4x$$

Short Solution Steps

Since \frac{4x^{2}-3}{x-2} and \frac{8x-3}{x-2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4x^{2}-3-\left(8x-3\right)}{x-2}$$

Do the multiplications in 4x^{2}-3-\left(8x-3\right).

$$\frac{4x^{2}-3-8x+3}{x-2}$$

Combine like terms in 4x^{2}-3-8x+3.

$$\frac{4x^{2}-8x}{x-2}$$

Factor the expressions that are not already factored in \frac{4x^{2}-8x}{x-2}.

$$\frac{4x\left(x-2\right)}{x-2}$$

Cancel out x-2 in both numerator and denominator.

$$4x$$