Solve frac{4x^{2}-2y+y}{2x^2y^2}-2x/2x^2y^2

$$\frac { 4 x ^ { 2 } - 2 y + y } { 2 x ^ { 2 } y ^ { 2 } } - \frac { 2 x } { 2 x ^ { 2 } y ^ { 2 } }$$

Evaluate

$$\frac{4x^{2}-2x-y}{2\left(xy\right)^{2}}$$

Short Solution Steps

Combine -2y and y to get -y.

$$\frac{4x^{2}-y}{2x^{2}y^{2}}-\frac{2x}{2x^{2}y^{2}}$$

Since \frac{4x^{2}-y}{2x^{2}y^{2}} and \frac{2x}{2x^{2}y^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4x^{2}-y-2x}{2x^{2}y^{2}}$$

Expand

$$-\frac{y+2x-4x^{2}}{2\left(xy\right)^{2}}$$

Short Solution Steps

Combine -2y and y to get -y.

$$\frac{4x^{2}-y}{2x^{2}y^{2}}-\frac{2x}{2x^{2}y^{2}}$$

Since \frac{4x^{2}-y}{2x^{2}y^{2}} and \frac{2x}{2x^{2}y^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4x^{2}-y-2x}{2x^{2}y^{2}}$$