Evaluate
\frac{\left(2x+1\right)^{2}}{\left(x-1\right)\left(x+2\right)}
Expand
\frac{4x^{2}+4x+1}{\left(x-1\right)\left(x+2\right)}
Graph
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\frac{\left(2x-1\right)\left(2x+1\right)}{\left(2x-1\right)\left(x+2\right)}+\frac{2x+1}{x-1}
Factor the expressions that are not already factored in \frac{4x^{2}-1}{2x^{2}+3x-2}.
\frac{2x+1}{x+2}+\frac{2x+1}{x-1}
Cancel out 2x-1 in both numerator and denominator.
\frac{\left(2x+1\right)\left(x-1\right)}{\left(x-1\right)\left(x+2\right)}+\frac{\left(2x+1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+2 and x-1 is \left(x-1\right)\left(x+2\right). Multiply \frac{2x+1}{x+2} times \frac{x-1}{x-1}. Multiply \frac{2x+1}{x-1} times \frac{x+2}{x+2}.
\frac{\left(2x+1\right)\left(x-1\right)+\left(2x+1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}
Since \frac{\left(2x+1\right)\left(x-1\right)}{\left(x-1\right)\left(x+2\right)} and \frac{\left(2x+1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)} have the same denominator, add them by adding their numerators.
\frac{2x^{2}-2x+x-1+2x^{2}+4x+x+2}{\left(x-1\right)\left(x+2\right)}
Do the multiplications in \left(2x+1\right)\left(x-1\right)+\left(2x+1\right)\left(x+2\right).
\frac{4x^{2}+4x+1}{\left(x-1\right)\left(x+2\right)}
Combine like terms in 2x^{2}-2x+x-1+2x^{2}+4x+x+2.
\frac{4x^{2}+4x+1}{x^{2}+x-2}
Expand \left(x-1\right)\left(x+2\right).
\frac{\left(2x-1\right)\left(2x+1\right)}{\left(2x-1\right)\left(x+2\right)}+\frac{2x+1}{x-1}
Factor the expressions that are not already factored in \frac{4x^{2}-1}{2x^{2}+3x-2}.
\frac{2x+1}{x+2}+\frac{2x+1}{x-1}
Cancel out 2x-1 in both numerator and denominator.
\frac{\left(2x+1\right)\left(x-1\right)}{\left(x-1\right)\left(x+2\right)}+\frac{\left(2x+1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+2 and x-1 is \left(x-1\right)\left(x+2\right). Multiply \frac{2x+1}{x+2} times \frac{x-1}{x-1}. Multiply \frac{2x+1}{x-1} times \frac{x+2}{x+2}.
\frac{\left(2x+1\right)\left(x-1\right)+\left(2x+1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}
Since \frac{\left(2x+1\right)\left(x-1\right)}{\left(x-1\right)\left(x+2\right)} and \frac{\left(2x+1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)} have the same denominator, add them by adding their numerators.
\frac{2x^{2}-2x+x-1+2x^{2}+4x+x+2}{\left(x-1\right)\left(x+2\right)}
Do the multiplications in \left(2x+1\right)\left(x-1\right)+\left(2x+1\right)\left(x+2\right).
\frac{4x^{2}+4x+1}{\left(x-1\right)\left(x+2\right)}
Combine like terms in 2x^{2}-2x+x-1+2x^{2}+4x+x+2.
\frac{4x^{2}+4x+1}{x^{2}+x-2}
Expand \left(x-1\right)\left(x+2\right).
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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