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\frac{4\left(x+2\right)}{\left(x+1\right)\left(x+2\right)}+\frac{3x-3}{x^{2}-1}
Factor the expressions that are not already factored in \frac{4x+8}{x^{2}+3x+2}.
\frac{4}{x+1}+\frac{3x-3}{x^{2}-1}
Cancel out x+2 in both numerator and denominator.
\frac{4}{x+1}+\frac{3\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}
Factor the expressions that are not already factored in \frac{3x-3}{x^{2}-1}.
\frac{4}{x+1}+\frac{3}{x+1}
Cancel out x-1 in both numerator and denominator.
\frac{7}{x+1}
Since \frac{4}{x+1} and \frac{3}{x+1} have the same denominator, add them by adding their numerators. Add 4 and 3 to get 7.
\frac{4\left(x+2\right)}{\left(x+1\right)\left(x+2\right)}+\frac{3x-3}{x^{2}-1}
Factor the expressions that are not already factored in \frac{4x+8}{x^{2}+3x+2}.
\frac{4}{x+1}+\frac{3x-3}{x^{2}-1}
Cancel out x+2 in both numerator and denominator.
\frac{4}{x+1}+\frac{3\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}
Factor the expressions that are not already factored in \frac{3x-3}{x^{2}-1}.
\frac{4}{x+1}+\frac{3}{x+1}
Cancel out x-1 in both numerator and denominator.
\frac{7}{x+1}
Since \frac{4}{x+1} and \frac{3}{x+1} have the same denominator, add them by adding their numerators. Add 4 and 3 to get 7.