Solve for x
x\in \left(-4,-2\right)
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4x+8>0 2x+8<0
For the quotient to be negative, 4x+8 and 2x+8 have to be of the opposite signs. Consider the case when 4x+8 is positive and 2x+8 is negative.
x\in \emptyset
This is false for any x.
2x+8>0 4x+8<0
Consider the case when 2x+8 is positive and 4x+8 is negative.
x\in \left(-4,-2\right)
The solution satisfying both inequalities is x\in \left(-4,-2\right).
x\in \left(-4,-2\right)
The final solution is the union of the obtained solutions.
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