\frac { 4 x + 3 } { 1 x + 2 } | \frac { 3 x + 8 } { 1 x ^ { 2 } - 2 x }
Evaluate
\frac{\left(4x+3\right)|3x+8|}{|x||x-2|\left(x+2\right)}
Differentiate w.r.t. x
\frac{12sign(3x+8)x^{4}+9sign(3x+8)x^{3}-8|3x+8|x^{3}-9|3x+8|x^{2}-48sign(3x+8)x^{2}-36xsign(3x+8)+12|3x+8|}{x|x|\left(x-2\right)|x-2|\left(x+2\right)^{2}}
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