Solve 4b/8*-3b/2

$$\frac { 4 b } { 8 } \times \frac { - 3 b } { 2 }$$

Evaluate

$$-\frac{3b^{2}}{4}$$

Solution Steps

Divide 4b by 8 to get \frac{1}{2}b.

$$\frac{1}{2}b\times \frac{-3b}{2}$$

Multiply \frac{1}{2} times \frac{-3b}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3b}{2\times 2}b$$

Multiply 2 and 2 to get 4.

$$\frac{-3b}{4}b$$

Express \frac{-3b}{4}b as a single fraction.

$$\frac{-3bb}{4}$$

Multiply b and b to get b^{2}.

$$\frac{-3b^{2}}{4}$$

Differentiate w.r.t. b

$$-\frac{3b}{2}$$