Solve 4ac/3b*9b^3/2ac^2=

$$\frac { 4 a c } { 3 b } \cdot \frac { 9 b ^ { 3 } } { 2 a c ^ { 2 } } =$$

Evaluate

$$\frac{6b^{2}}{c}$$

Solution Steps

Multiply \frac{4ac}{3b} times \frac{9b^{3}}{2ac^{2}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4ac\times 9b^{3}}{3b\times 2ac^{2}}$$

Cancel out 2\times 3abc in both numerator and denominator.

$$\frac{2\times 3b^{2}}{c}$$

Multiply 2 and 3 to get 6.

$$\frac{6b^{2}}{c}$$

Differentiate w.r.t. b

$$\frac{12b}{c}$$