Solve 4a^2bc^3/24b^-2

$$\frac { 4 a ^ { 2 } b c ^ { 3 } } { 24 b ^ { - 2 } }$$

Evaluate

$$\frac{a^{2}\left(bc\right)^{3}}{6}$$

Solution Steps

Cancel out 4 in both numerator and denominator.

$$\frac{ba^{2}c^{3}}{6b^{-2}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{a^{2}b^{3}c^{3}}{6}$$

Differentiate w.r.t. a

$$\frac{a\left(bc\right)^{3}}{3}$$