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\frac{\left(4-7i\right)\left(3-5i\right)}{\left(3+5i\right)\left(3-5i\right)}
Multiply both numerator and denominator by the complex conjugate of the denominator, 3-5i.
\frac{\left(4-7i\right)\left(3-5i\right)}{3^{2}-5^{2}i^{2}}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(4-7i\right)\left(3-5i\right)}{34}
By definition, i^{2} is -1. Calculate the denominator.
\frac{4\times 3+4\times \left(-5i\right)-7i\times 3-7\left(-5\right)i^{2}}{34}
Multiply complex numbers 4-7i and 3-5i like you multiply binomials.
\frac{4\times 3+4\times \left(-5i\right)-7i\times 3-7\left(-5\right)\left(-1\right)}{34}
By definition, i^{2} is -1.
\frac{12-20i-21i-35}{34}
Do the multiplications in 4\times 3+4\times \left(-5i\right)-7i\times 3-7\left(-5\right)\left(-1\right).
\frac{12-35+\left(-20-21\right)i}{34}
Combine the real and imaginary parts in 12-20i-21i-35.
\frac{-23-41i}{34}
Do the additions in 12-35+\left(-20-21\right)i.
-\frac{23}{34}-\frac{41}{34}i
Divide -23-41i by 34 to get -\frac{23}{34}-\frac{41}{34}i.
Re(\frac{\left(4-7i\right)\left(3-5i\right)}{\left(3+5i\right)\left(3-5i\right)})
Multiply both numerator and denominator of \frac{4-7i}{3+5i} by the complex conjugate of the denominator, 3-5i.
Re(\frac{\left(4-7i\right)\left(3-5i\right)}{3^{2}-5^{2}i^{2}})
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
Re(\frac{\left(4-7i\right)\left(3-5i\right)}{34})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{4\times 3+4\times \left(-5i\right)-7i\times 3-7\left(-5\right)i^{2}}{34})
Multiply complex numbers 4-7i and 3-5i like you multiply binomials.
Re(\frac{4\times 3+4\times \left(-5i\right)-7i\times 3-7\left(-5\right)\left(-1\right)}{34})
By definition, i^{2} is -1.
Re(\frac{12-20i-21i-35}{34})
Do the multiplications in 4\times 3+4\times \left(-5i\right)-7i\times 3-7\left(-5\right)\left(-1\right).
Re(\frac{12-35+\left(-20-21\right)i}{34})
Combine the real and imaginary parts in 12-20i-21i-35.
Re(\frac{-23-41i}{34})
Do the additions in 12-35+\left(-20-21\right)i.
Re(-\frac{23}{34}-\frac{41}{34}i)
Divide -23-41i by 34 to get -\frac{23}{34}-\frac{41}{34}i.
-\frac{23}{34}
The real part of -\frac{23}{34}-\frac{41}{34}i is -\frac{23}{34}.