Solve 4-2/5/3+frac{3{10}}

$$\frac { 4 - \frac { 2 } { 5 } } { 3 + \frac { 3 } { 10 } }$$

Evaluate

$$\frac{12}{11}\approx 1.090909091$$

Solution Steps

Convert 4 to fraction \frac{20}{5}.

$$\frac{\frac{20}{5}-\frac{2}{5}}{3+\frac{3}{10}}$$

Since \frac{20}{5} and \frac{2}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{20-2}{5}}{3+\frac{3}{10}}$$

Subtract 2 from 20 to get 18.

$$\frac{\frac{18}{5}}{3+\frac{3}{10}}$$

Convert 3 to fraction \frac{30}{10}.

$$\frac{\frac{18}{5}}{\frac{30}{10}+\frac{3}{10}}$$

Since \frac{30}{10} and \frac{3}{10} have the same denominator, add them by adding their numerators.

$$\frac{\frac{18}{5}}{\frac{30+3}{10}}$$

Add 30 and 3 to get 33.

$$\frac{\frac{18}{5}}{\frac{33}{10}}$$

Divide \frac{18}{5} by \frac{33}{10} by multiplying \frac{18}{5} by the reciprocal of \frac{33}{10}.

$$\frac{18}{5}\times \frac{10}{33}$$

Multiply \frac{18}{5} times \frac{10}{33} by multiplying numerator times numerator and denominator times denominator.

$$\frac{18\times 10}{5\times 33}$$

Do the multiplications in the fraction \frac{18\times 10}{5\times 33}.

$$\frac{180}{165}$$

Reduce the fraction \frac{180}{165} to lowest terms by extracting and canceling out 15.

$$\frac{12}{11}$$

Factor

$$\frac{2 ^ {2} \cdot 3}{11} = 1\frac{1}{11} = 1.0909090909090908$$