Solve 4(9+2)+8(10-3)/6(4-2)-2^2

$$\frac { 4 ( 9 + 2 ) + 8 ( 10 - 3 ) } { 6 ( 4 - 2 ) - 2 ^ { 2 } }$$

Evaluate

$$\frac{25}{2}=12.5$$

Solution Steps

Add 9 and 2 to get 11.

$$\frac{4\times 11+8\left(10-3\right)}{6\left(4-2\right)-2^{2}}$$

Multiply 4 and 11 to get 44.

$$\frac{44+8\left(10-3\right)}{6\left(4-2\right)-2^{2}}$$

Subtract 3 from 10 to get 7.

$$\frac{44+8\times 7}{6\left(4-2\right)-2^{2}}$$

Multiply 8 and 7 to get 56.

$$\frac{44+56}{6\left(4-2\right)-2^{2}}$$

Add 44 and 56 to get 100.

$$\frac{100}{6\left(4-2\right)-2^{2}}$$

Subtract 2 from 4 to get 2.

$$\frac{100}{6\times 2-2^{2}}$$

Multiply 6 and 2 to get 12.

$$\frac{100}{12-2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{100}{12-4}$$

Subtract 4 from 12 to get 8.

$$\frac{100}{8}$$

Reduce the fraction \frac{100}{8} to lowest terms by extracting and canceling out 4.

$$\frac{25}{2}$$

Factor

$$\frac{5 ^ {2}}{2} = 12\frac{1}{2} = 12.5$$