Solve 4(-1/2)^2/-1/2^2-4

$$\frac { 4 ( - 1 / 2 ) ^ { 2 } } { - 1 / 2 ^ { 2 } - 4 }$$

Evaluate

$$-\frac{4}{17}\approx -0.235294118$$

Solution Steps

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{4\times \frac{1}{4}}{-\left(\frac{1}{2}\right)^{2}-4}$$

Cancel out 4 and 4.

$$\frac{1}{-\left(\frac{1}{2}\right)^{2}-4}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{-\frac{1}{4}-4}$$

Convert 4 to fraction \frac{16}{4}.

$$\frac{1}{-\frac{1}{4}-\frac{16}{4}}$$

Since -\frac{1}{4} and \frac{16}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{\frac{-1-16}{4}}$$

Subtract 16 from -1 to get -17.

$$\frac{1}{-\frac{17}{4}}$$

Divide 1 by -\frac{17}{4} by multiplying 1 by the reciprocal of -\frac{17}{4}.

$$1\left(-\frac{4}{17}\right)$$

Multiply 1 and -\frac{4}{17} to get -\frac{4}{17}.

$$-\frac{4}{17}$$

Factor

$$-\frac{4}{17} = -0.23529411764705882$$