Solve for x
x = \frac{2 \sqrt{326} + 3}{35} \approx 1.117455433
x=\frac{3-2\sqrt{326}}{35}\approx -0.946026862
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\left(x+1\right)\times 4+\left(x-1\right)\times 2=35\left(x-1\right)\left(x+1\right)
Variable x cannot be equal to any of the values -1,1 since division by zero is not defined. Multiply both sides of the equation by \left(x-1\right)\left(x+1\right), the least common multiple of x-1,x+1.
4x+4+\left(x-1\right)\times 2=35\left(x-1\right)\left(x+1\right)
Use the distributive property to multiply x+1 by 4.
4x+4+2x-2=35\left(x-1\right)\left(x+1\right)
Use the distributive property to multiply x-1 by 2.
6x+4-2=35\left(x-1\right)\left(x+1\right)
Combine 4x and 2x to get 6x.
6x+2=35\left(x-1\right)\left(x+1\right)
Subtract 2 from 4 to get 2.
6x+2=\left(35x-35\right)\left(x+1\right)
Use the distributive property to multiply 35 by x-1.
6x+2=35x^{2}-35
Use the distributive property to multiply 35x-35 by x+1 and combine like terms.
6x+2-35x^{2}=-35
Subtract 35x^{2} from both sides.
6x+2-35x^{2}+35=0
Add 35 to both sides.
6x+37-35x^{2}=0
Add 2 and 35 to get 37.
-35x^{2}+6x+37=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-6±\sqrt{6^{2}-4\left(-35\right)\times 37}}{2\left(-35\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -35 for a, 6 for b, and 37 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-6±\sqrt{36-4\left(-35\right)\times 37}}{2\left(-35\right)}
Square 6.
x=\frac{-6±\sqrt{36+140\times 37}}{2\left(-35\right)}
Multiply -4 times -35.
x=\frac{-6±\sqrt{36+5180}}{2\left(-35\right)}
Multiply 140 times 37.
x=\frac{-6±\sqrt{5216}}{2\left(-35\right)}
Add 36 to 5180.
x=\frac{-6±4\sqrt{326}}{2\left(-35\right)}
Take the square root of 5216.
x=\frac{-6±4\sqrt{326}}{-70}
Multiply 2 times -35.
x=\frac{4\sqrt{326}-6}{-70}
Now solve the equation x=\frac{-6±4\sqrt{326}}{-70} when ± is plus. Add -6 to 4\sqrt{326}.
x=\frac{3-2\sqrt{326}}{35}
Divide -6+4\sqrt{326} by -70.
x=\frac{-4\sqrt{326}-6}{-70}
Now solve the equation x=\frac{-6±4\sqrt{326}}{-70} when ± is minus. Subtract 4\sqrt{326} from -6.
x=\frac{2\sqrt{326}+3}{35}
Divide -6-4\sqrt{326} by -70.
x=\frac{3-2\sqrt{326}}{35} x=\frac{2\sqrt{326}+3}{35}
The equation is now solved.
\left(x+1\right)\times 4+\left(x-1\right)\times 2=35\left(x-1\right)\left(x+1\right)
Variable x cannot be equal to any of the values -1,1 since division by zero is not defined. Multiply both sides of the equation by \left(x-1\right)\left(x+1\right), the least common multiple of x-1,x+1.
4x+4+\left(x-1\right)\times 2=35\left(x-1\right)\left(x+1\right)
Use the distributive property to multiply x+1 by 4.
4x+4+2x-2=35\left(x-1\right)\left(x+1\right)
Use the distributive property to multiply x-1 by 2.
6x+4-2=35\left(x-1\right)\left(x+1\right)
Combine 4x and 2x to get 6x.
6x+2=35\left(x-1\right)\left(x+1\right)
Subtract 2 from 4 to get 2.
6x+2=\left(35x-35\right)\left(x+1\right)
Use the distributive property to multiply 35 by x-1.
6x+2=35x^{2}-35
Use the distributive property to multiply 35x-35 by x+1 and combine like terms.
6x+2-35x^{2}=-35
Subtract 35x^{2} from both sides.
6x-35x^{2}=-35-2
Subtract 2 from both sides.
6x-35x^{2}=-37
Subtract 2 from -35 to get -37.
-35x^{2}+6x=-37
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-35x^{2}+6x}{-35}=-\frac{37}{-35}
Divide both sides by -35.
x^{2}+\frac{6}{-35}x=-\frac{37}{-35}
Dividing by -35 undoes the multiplication by -35.
x^{2}-\frac{6}{35}x=-\frac{37}{-35}
Divide 6 by -35.
x^{2}-\frac{6}{35}x=\frac{37}{35}
Divide -37 by -35.
x^{2}-\frac{6}{35}x+\left(-\frac{3}{35}\right)^{2}=\frac{37}{35}+\left(-\frac{3}{35}\right)^{2}
Divide -\frac{6}{35}, the coefficient of the x term, by 2 to get -\frac{3}{35}. Then add the square of -\frac{3}{35} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-\frac{6}{35}x+\frac{9}{1225}=\frac{37}{35}+\frac{9}{1225}
Square -\frac{3}{35} by squaring both the numerator and the denominator of the fraction.
x^{2}-\frac{6}{35}x+\frac{9}{1225}=\frac{1304}{1225}
Add \frac{37}{35} to \frac{9}{1225} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-\frac{3}{35}\right)^{2}=\frac{1304}{1225}
Factor x^{2}-\frac{6}{35}x+\frac{9}{1225}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{3}{35}\right)^{2}}=\sqrt{\frac{1304}{1225}}
Take the square root of both sides of the equation.
x-\frac{3}{35}=\frac{2\sqrt{326}}{35} x-\frac{3}{35}=-\frac{2\sqrt{326}}{35}
Simplify.
x=\frac{2\sqrt{326}+3}{35} x=\frac{3-2\sqrt{326}}{35}
Add \frac{3}{35} to both sides of the equation.
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Limits
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