Solve 4/xquadH3/-x

$$\frac { 4 } { x } \quad H \frac { 3 } { - x }$$

Evaluate

$$-\frac{12H}{x^{2}}$$

Short Solution Steps

Express \frac{4}{x}H as a single fraction.

$$\frac{4H}{x}\times \frac{3}{-x}$$

Multiply \frac{4H}{x} times \frac{3}{-x} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4H\times 3}{x\left(-x\right)}$$

Multiply 4 and 3 to get 12.

$$\frac{12H}{x\left(-x\right)}$$

Multiply x and x to get x^{2}.

$$\frac{12H}{x^{2}\left(-1\right)}$$

Cancel out -1 in both numerator and denominator.

$$\frac{-12H}{x^{2}}$$

Differentiate w.r.t. x

$$\frac{24H}{x^{3}}$$