Solve for x
x=-1
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Linear Equation
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\frac { 4 } { x } + 1 \frac { 1 } { 2 } = \frac { 5 } { 2 x }
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2\times 4+x\left(1\times 2+1\right)=5
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2x, the least common multiple of x,2,2x.
8+x\left(1\times 2+1\right)=5
Multiply 2 and 4 to get 8.
8+x\left(2+1\right)=5
Multiply 1 and 2 to get 2.
8+x\times 3=5
Add 2 and 1 to get 3.
x\times 3=5-8
Subtract 8 from both sides.
x\times 3=-3
Subtract 8 from 5 to get -3.
x=\frac{-3}{3}
Divide both sides by 3.
x=-1
Divide -3 by 3 to get -1.
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{ x } ^ { 2 } - 4 x - 5 = 0
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y = 3x + 4
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}