Solve 4/x+1-3/2x-1

$$\frac { 4 } { x + 1 } - \frac { 3 } { 2 x - 1 }$$

Evaluate

$$\frac{5x-7}{\left(2x-1\right)\left(x+1\right)}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+1 and 2x-1 is \left(2x-1\right)\left(x+1\right). Multiply \frac{4}{x+1} times \frac{2x-1}{2x-1}. Multiply \frac{3}{2x-1} times \frac{x+1}{x+1}.

$$\frac{4\left(2x-1\right)}{\left(2x-1\right)\left(x+1\right)}-\frac{3\left(x+1\right)}{\left(2x-1\right)\left(x+1\right)}$$

Since \frac{4\left(2x-1\right)}{\left(2x-1\right)\left(x+1\right)} and \frac{3\left(x+1\right)}{\left(2x-1\right)\left(x+1\right)} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4\left(2x-1\right)-3\left(x+1\right)}{\left(2x-1\right)\left(x+1\right)}$$

Do the multiplications in 4\left(2x-1\right)-3\left(x+1\right).

$$\frac{8x-4-3x-3}{\left(2x-1\right)\left(x+1\right)}$$

Combine like terms in 8x-4-3x-3.

$$\frac{5x-7}{\left(2x-1\right)\left(x+1\right)}$$

Expand \left(2x-1\right)\left(x+1\right).

$$\frac{5x-7}{2x^{2}+x-1}$$

Differentiate w.r.t. x

$$\frac{2\left(1+14x-5x^{2}\right)}{4x^{4}+4x^{3}-3x^{2}-2x+1}$$

Steps Using Derivative Rule for Quotient

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+1 and 2x-1 is \left(2x-1\right)\left(x+1\right). Multiply \frac{4}{x+1} times \frac{2x-1}{2x-1}. Multiply \frac{3}{2x-1} times \frac{x+1}{x+1}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{4\left(2x-1\right)}{\left(2x-1\right)\left(x+1\right)}-\frac{3\left(x+1\right)}{\left(2x-1\right)\left(x+1\right)})$$

Since \frac{4\left(2x-1\right)}{\left(2x-1\right)\left(x+1\right)} and \frac{3\left(x+1\right)}{\left(2x-1\right)\left(x+1\right)} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{4\left(2x-1\right)-3\left(x+1\right)}{\left(2x-1\right)\left(x+1\right)})$$

Do the multiplications in 4\left(2x-1\right)-3\left(x+1\right).

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{8x-4-3x-3}{\left(2x-1\right)\left(x+1\right)})$$

Combine like terms in 8x-4-3x-3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5x-7}{\left(2x-1\right)\left(x+1\right)})$$

Apply the distributive property by multiplying each term of 2x-1 by each term of x+1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5x-7}{2x^{2}+2x-x-1})$$

Combine 2x and -x to get x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{5x-7}{2x^{2}+x-1})$$

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(2x^{2}+x^{1}-1\right)\frac{\mathrm{d}}{\mathrm{d}x}(5x^{1}-7)-\left(5x^{1}-7\right)\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}+x^{1}-1)}{\left(2x^{2}+x^{1}-1\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(2x^{2}+x^{1}-1\right)\times 5x^{1-1}-\left(5x^{1}-7\right)\left(2\times 2x^{2-1}+x^{1-1}\right)}{\left(2x^{2}+x^{1}-1\right)^{2}}$$

Simplify.

$$\frac{\left(2x^{2}+x^{1}-1\right)\times 5x^{0}-\left(5x^{1}-7\right)\left(4x^{1}+x^{0}\right)}{\left(2x^{2}+x^{1}-1\right)^{2}}$$

Multiply 2x^{2}+x^{1}-1 times 5x^{0}.

$$\frac{2x^{2}\times 5x^{0}+x^{1}\times 5x^{0}-5x^{0}-\left(5x^{1}-7\right)\left(4x^{1}+x^{0}\right)}{\left(2x^{2}+x^{1}-1\right)^{2}}$$

Multiply 5x^{1}-7 times 4x^{1}+x^{0}.

$$\frac{2x^{2}\times 5x^{0}+x^{1}\times 5x^{0}-5x^{0}-\left(5x^{1}\times 4x^{1}+5x^{1}x^{0}-7\times 4x^{1}-7x^{0}\right)}{\left(2x^{2}+x^{1}-1\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{2\times 5x^{2}+5x^{1}-5x^{0}-\left(5\times 4x^{1+1}+5x^{1}-7\times 4x^{1}-7x^{0}\right)}{\left(2x^{2}+x^{1}-1\right)^{2}}$$

Simplify.

$$\frac{10x^{2}+5x^{1}-5x^{0}-\left(20x^{2}+5x^{1}-28x^{1}-7x^{0}\right)}{\left(2x^{2}+x^{1}-1\right)^{2}}$$

Combine like terms.

$$\frac{-10x^{2}+28x^{1}+2x^{0}}{\left(2x^{2}+x^{1}-1\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{-10x^{2}+28x+2x^{0}}{\left(2x^{2}+x-1\right)^{2}}$$

For any term t except 0, t^{0}=1.

$$\frac{-10x^{2}+28x+2\times 1}{\left(2x^{2}+x-1\right)^{2}}$$

For any term t, t\times 1=t and 1t=t.

$$\frac{-10x^{2}+28x+2}{\left(2x^{2}+x-1\right)^{2}}$$