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\frac{4\left(x-2\right)}{\left(x-2\right)\left(x+1\right)}-\frac{2\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+1 and x-2 is \left(x-2\right)\left(x+1\right). Multiply \frac{4}{x+1} times \frac{x-2}{x-2}. Multiply \frac{2}{x-2} times \frac{x+1}{x+1}.
\frac{4\left(x-2\right)-2\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}
Since \frac{4\left(x-2\right)}{\left(x-2\right)\left(x+1\right)} and \frac{2\left(x+1\right)}{\left(x-2\right)\left(x+1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{4x-8-2x-2}{\left(x-2\right)\left(x+1\right)}
Do the multiplications in 4\left(x-2\right)-2\left(x+1\right).
\frac{2x-10}{\left(x-2\right)\left(x+1\right)}
Combine like terms in 4x-8-2x-2.
\frac{2x-10}{x^{2}-x-2}
Expand \left(x-2\right)\left(x+1\right).