Solve 4/9x^6y^2+7/12x^3y^8=

$$\frac { 4 } { 9 x ^ { 6 } y ^ { 2 } } + \frac { 7 } { 12 x ^ { 3 } y ^ { 8 } } =$$

Evaluate

$$\frac{4}{9y^{2}x^{6}}+\frac{7}{12x^{3}y^{8}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 9x^{6}y^{2} and 12x^{3}y^{8} is 36x^{6}y^{8}. Multiply \frac{4}{9x^{6}y^{2}} times \frac{4y^{6}}{4y^{6}}. Multiply \frac{7}{12x^{3}y^{8}} times \frac{3x^{3}}{3x^{3}}.

$$\frac{4\times 4y^{6}}{36x^{6}y^{8}}+\frac{7\times 3x^{3}}{36x^{6}y^{8}}$$

Since \frac{4\times 4y^{6}}{36x^{6}y^{8}} and \frac{7\times 3x^{3}}{36x^{6}y^{8}} have the same denominator, add them by adding their numerators.

$$\frac{4\times 4y^{6}+7\times 3x^{3}}{36x^{6}y^{8}}$$

Do the multiplications in 4\times 4y^{6}+7\times 3x^{3}.

$$\frac{16y^{6}+21x^{3}}{36x^{6}y^{8}}$$

Factor

$$\frac{\left(16+\frac{21x^{3}}{y^{6}}\right)\times \left(\frac{1}{x^{3}}\right)^{2}}{36y^{2}}$$