Solve 4/9x-8/3+96/366

$$\frac { 4 } { 9 } x - \frac { 8 } { 3 } + \frac { 96 } { 366 }$$

Evaluate

$$\frac{4x}{9}-\frac{440}{183}$$

Solution Steps

Reduce the fraction \frac{96}{366} to lowest terms by extracting and canceling out 6.

$$\frac{4}{9}x-\frac{8}{3}+\frac{16}{61}$$

Least common multiple of 3 and 61 is 183. Convert -\frac{8}{3} and \frac{16}{61} to fractions with denominator 183.

$$\frac{4}{9}x-\frac{488}{183}+\frac{48}{183}$$

Since -\frac{488}{183} and \frac{48}{183} have the same denominator, add them by adding their numerators.

$$\frac{4}{9}x+\frac{-488+48}{183}$$

Add -488 and 48 to get -440.

$$\frac{4}{9}x-\frac{440}{183}$$

Factor

$$\frac{4\left(61x-330\right)}{549}$$

Solution Steps

Factor out \frac{4}{549}.

$$\frac{4\left(61x-330\right)}{549}$$

Consider 61x-366+36. Multiply and combine like terms.

$$61x-330$$

Rewrite the complete factored expression.

$$\frac{4\left(61x-330\right)}{549}$$