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\frac{4-9y^{2}}{9}
Factor out \frac{1}{9}.
\left(2-3y\right)\left(2+3y\right)
Consider 4-9y^{2}. Rewrite 4-9y^{2} as 2^{2}-\left(3y\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(-3y+2\right)\left(3y+2\right)
Reorder the terms.
\frac{\left(-3y+2\right)\left(3y+2\right)}{9}
Rewrite the complete factored expression.