Solve 4/9text{bedividedtoget}8/11

$$\frac { 4 } { 9 } \text { be divided to get } \frac { 8 } { 11 }$$

Evaluate

$$-\frac{32bgovt^{2}\left(ed\right)^{3}}{99}$$

Solution Steps

Multiply e and e to get e^{2}.

$$\frac{4}{9}be^{2}dividdtoget\times \frac{8}{11}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{4}{9}be^{3}dividdtogt\times \frac{8}{11}$$

Multiply d and d to get d^{2}.

$$\frac{4}{9}be^{3}d^{2}ividtogt\times \frac{8}{11}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{4}{9}be^{3}d^{3}ivitogt\times \frac{8}{11}$$

Multiply t and t to get t^{2}.

$$\frac{4}{9}be^{3}d^{3}ivit^{2}og\times \frac{8}{11}$$

Multiply \frac{4}{9} and i to get \frac{4}{9}i.

$$\frac{4}{9}ibe^{3}d^{3}vit^{2}og\times \frac{8}{11}$$

Multiply \frac{4}{9}i and i to get -\frac{4}{9}.

$$-\frac{4}{9}be^{3}d^{3}vt^{2}og\times \frac{8}{11}$$

Multiply -\frac{4}{9} times \frac{8}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-4\times 8}{9\times 11}be^{3}d^{3}vt^{2}og$$

Do the multiplications in the fraction \frac{-4\times 8}{9\times 11}.

$$\frac{-32}{99}be^{3}d^{3}vt^{2}og$$

Fraction \frac{-32}{99} can be rewritten as -\frac{32}{99} by extracting the negative sign.

$$-\frac{32}{99}be^{3}d^{3}vt^{2}og$$