Solve 4/9div1/3+7/10

$$\frac { 4 } { 9 } \div \frac { 1 } { 3 } + \frac { 7 } { 10 }$$

Evaluate

$$\frac{61}{30}\approx 2.033333333$$

Solution Steps

Divide \frac{4}{9} by \frac{1}{3} by multiplying \frac{4}{9} by the reciprocal of \frac{1}{3}.

$$\frac{4}{9}\times 3+\frac{7}{10}$$

Express \frac{4}{9}\times 3 as a single fraction.

$$\frac{4\times 3}{9}+\frac{7}{10}$$

Multiply 4 and 3 to get 12.

$$\frac{12}{9}+\frac{7}{10}$$

Reduce the fraction \frac{12}{9} to lowest terms by extracting and canceling out 3.

$$\frac{4}{3}+\frac{7}{10}$$

Least common multiple of 3 and 10 is 30. Convert \frac{4}{3} and \frac{7}{10} to fractions with denominator 30.

$$\frac{40}{30}+\frac{21}{30}$$

Since \frac{40}{30} and \frac{21}{30} have the same denominator, add them by adding their numerators.

$$\frac{40+21}{30}$$

Add 40 and 21 to get 61.

$$\frac{61}{30}$$

Factor

$$\frac{61}{2 \cdot 3 \cdot 5} = 2\frac{1}{30} = 2.033333333333333$$