Solve 4/7y-2=3/7y+3/14

$$\frac { 4 } { 7 } y - 2 = \frac { 3 } { 7 } y + \frac { 3 } { 14 }$$

Solve for y

$$y = \frac{31}{2} = 15\frac{1}{2} = 15.5$$

Steps for Solving Linear Equation

Subtract \frac{3}{7}y from both sides.

$$\frac{4}{7}y-2-\frac{3}{7}y=\frac{3}{14}$$

Combine \frac{4}{7}y and -\frac{3}{7}y to get \frac{1}{7}y.

$$\frac{1}{7}y-2=\frac{3}{14}$$

Add 2 to both sides.

$$\frac{1}{7}y=\frac{3}{14}+2$$

Convert 2 to fraction \frac{28}{14}.

$$\frac{1}{7}y=\frac{3}{14}+\frac{28}{14}$$

Since \frac{3}{14} and \frac{28}{14} have the same denominator, add them by adding their numerators.

$$\frac{1}{7}y=\frac{3+28}{14}$$

Add 3 and 28 to get 31.

$$\frac{1}{7}y=\frac{31}{14}$$

Multiply both sides by 7, the reciprocal of \frac{1}{7}.

$$y=\frac{31}{14}\times 7$$

Express \frac{31}{14}\times 7 as a single fraction.

$$y=\frac{31\times 7}{14}$$

Multiply 31 and 7 to get 217.

$$y=\frac{217}{14}$$

Reduce the fraction \frac{217}{14} to lowest terms by extracting and canceling out 7.

$$y=\frac{31}{2}$$