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\frac{2\left(2+x-3x^{2}\right)}{7}
Factor out \frac{2}{7}.
-3x^{2}+x+2
Consider 2+x-3x^{2}. Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=1 ab=-3\times 2=-6
Factor the expression by grouping. First, the expression needs to be rewritten as -3x^{2}+ax+bx+2. To find a and b, set up a system to be solved.
-1,6 -2,3
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -6.
-1+6=5 -2+3=1
Calculate the sum for each pair.
a=3 b=-2
The solution is the pair that gives sum 1.
\left(-3x^{2}+3x\right)+\left(-2x+2\right)
Rewrite -3x^{2}+x+2 as \left(-3x^{2}+3x\right)+\left(-2x+2\right).
3x\left(-x+1\right)+2\left(-x+1\right)
Factor out 3x in the first and 2 in the second group.
\left(-x+1\right)\left(3x+2\right)
Factor out common term -x+1 by using distributive property.
\frac{2\left(-x+1\right)\left(3x+2\right)}{7}
Rewrite the complete factored expression.