Solve 4/63+1/14+1/18+1/21

$$\frac { 4 } { 63 } + \frac { 1 } { 14 } + \frac { 1 } { 18 } + \frac { 1 } { 21 }$$

Evaluate

$$\frac{5}{21}\approx 0.238095238$$

Solution Steps

Least common multiple of 63 and 14 is 126. Convert \frac{4}{63} and \frac{1}{14} to fractions with denominator 126.

$$\frac{8}{126}+\frac{9}{126}+\frac{1}{18}+\frac{1}{21}$$

Since \frac{8}{126} and \frac{9}{126} have the same denominator, add them by adding their numerators.

$$\frac{8+9}{126}+\frac{1}{18}+\frac{1}{21}$$

Add 8 and 9 to get 17.

$$\frac{17}{126}+\frac{1}{18}+\frac{1}{21}$$

Least common multiple of 126 and 18 is 126. Convert \frac{17}{126} and \frac{1}{18} to fractions with denominator 126.

$$\frac{17}{126}+\frac{7}{126}+\frac{1}{21}$$

Since \frac{17}{126} and \frac{7}{126} have the same denominator, add them by adding their numerators.

$$\frac{17+7}{126}+\frac{1}{21}$$

Add 17 and 7 to get 24.

$$\frac{24}{126}+\frac{1}{21}$$

Reduce the fraction \frac{24}{126} to lowest terms by extracting and canceling out 6.

$$\frac{4}{21}+\frac{1}{21}$$

Since \frac{4}{21} and \frac{1}{21} have the same denominator, add them by adding their numerators.

$$\frac{4+1}{21}$$

Add 4 and 1 to get 5.

$$\frac{5}{21}$$

Factor

$$\frac{5}{3 \cdot 7} = 0.23809523809523808$$