Solve 4/60quad1/12+4/9=

$$\frac { 4 } { 60 } \quad \frac { 1 } { 12 } + \frac { 4 } { 9 } =$$

Evaluate

$$\frac{9}{20}=0.45$$

Solution Steps

Reduce the fraction \frac{4}{60} to lowest terms by extracting and canceling out 4.

$$\frac{1}{15}\times \frac{1}{12}+\frac{4}{9}$$

Multiply \frac{1}{15} times \frac{1}{12} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 1}{15\times 12}+\frac{4}{9}$$

Do the multiplications in the fraction \frac{1\times 1}{15\times 12}.

$$\frac{1}{180}+\frac{4}{9}$$

Least common multiple of 180 and 9 is 180. Convert \frac{1}{180} and \frac{4}{9} to fractions with denominator 180.

$$\frac{1}{180}+\frac{80}{180}$$

Since \frac{1}{180} and \frac{80}{180} have the same denominator, add them by adding their numerators.

$$\frac{1+80}{180}$$

Add 1 and 80 to get 81.

$$\frac{81}{180}$$

Reduce the fraction \frac{81}{180} to lowest terms by extracting and canceling out 9.

$$\frac{9}{20}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {2} \cdot 5} = 0.45$$