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\frac{16x^{3}-10x^{2}-95x+50}{20}
Factor out \frac{1}{20}.
\left(2x-5\right)\left(8x^{2}+15x-10\right)
Consider 16x^{3}-10x^{2}-95x+50. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 50 and q divides the leading coefficient 16. One such root is \frac{5}{2}. Factor the polynomial by dividing it by 2x-5.
\frac{\left(2x-5\right)\left(8x^{2}+15x-10\right)}{20}
Rewrite the complete factored expression. Polynomial 8x^{2}+15x-10 is not factored since it does not have any rational roots.